For all \(x\neq\pm 6\), \[\frac{x^2 - 5x -6 } {x^2 – 36 } =\]
\(\displaystyle{\frac{-5x}{6}}\) | |
\(\displaystyle{\frac{x+1}{x+6}}\) | |
\(\displaystyle{\frac{x-3}{x+6} }\) | |
\(\displaystyle{\frac{x+6}{x-12}}\) | |
\(\displaystyle{-5x+\frac{1}{6}}\) |
After watching the video, try this problem to practice more.
For all \(x\neq\pm 3\), \[\frac{x^2 - 2x – 15} {x^2 – 9} =\]
\(\displaystyle{\frac{-2x + 5}{3}}\) | |
\(\displaystyle{\frac{x-5}{x+3}}\) | |
\(\displaystyle{\frac{x-5}{x-3}}\) | |
\(\displaystyle{\frac{5}{3}}\) | |
\(\displaystyle{-\frac{5}{3}}\) |