For all \(x\neq\pm 6\), \[\frac{x^2 - 5x -6 } {x^2 - 36 } =\]

\(\displaystyle{\frac{-5x}{6}}\) | |

\(\displaystyle{\frac{x+1}{x+6}}\) | |

\(\displaystyle{\frac{x-3}{x+6} }\) | |

\(\displaystyle{\frac{x+6}{x-12}}\) | |

\(\displaystyle{-5x+\frac{1}{6}}\) |

After watching the video, try this problem to practice more.

For all \(x\neq\pm 3\), \[\frac{x^2 - 2x - 15} {x^2 - 9} =\]

\(\displaystyle{\frac{-2x + 5}{3}}\) | |

\(\displaystyle{\frac{x-5}{x+3}}\) | |

\(\displaystyle{\frac{x-5}{x-3}}\) | |

\(\displaystyle{\frac{5}{3}}\) | |

\(\displaystyle{-\frac{5}{3}}\) |